The correct relation between limit of resolution and resolving power is
- ALimit of resolution $= \frac{1}{\text{resolving power}}$
- BLimit of resolution $\propto$ resolving power
- CLimit of resolution $\propto \frac{1}{\text{resolving power}}$
- DLimit of resolution $\propto (1 - \text{resolving power})$
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$A$ person is observing a bacteria through a compound microscope. For better analysis and to improve the resolving power,he should:
The diameter of the objective lens of a telescope is $250\, cm$. For light of wavelength $600\, nm$ coming from a distant object, the limit of resolution of the telescope is close to:
Two points separated by a distance of $0.1 \ mm$ can just be seen in a microscope when light of wavelength $6000 \ Å$ is used. If the light of wavelength $4800 \ Å$ is used,the limit of resolution will become: (in $mm$)
The diameter of the objective of a telescope is $10 \, cm$. There are two objects at a distance of $1 \, km$ from it. What should be the minimum distance between these two objects so that their images are seen as separate by this telescope? The wavelength of light is $5000 \, \mathring{A}$.
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View SolutionAn electron microscope is operated at $40 \ kV$. The ratio of the resolving power of this microscope to another one which uses yellow light of wavelength $6 \times 10^{-7} \ m$ is:
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